Calculus 8th Edition

Published by Cengage
ISBN 10: 1285740629
ISBN 13: 978-1-28574-062-1

Chapter 10 - Parametric Equations and Polar Coordinates - 10.5 Conic Sections - 10.5 Exercises - Page 720: 28


Foci: $( 1,\pm \sqrt 2)$ and vertices: $(1,\pm1,)$

Work Step by Step

Given: $x^2-2x=y^2-2$ $\frac{(y-0)^{2}}{1^2}-\frac{(x-1)^{2}}{1^2}=1$, which represents an equation of an hyperbola with $c^{2}=1+1=2$ or, $c=\sqrt 2$ Hence, Foci: $( 1,\pm \sqrt 2)$ and vertices: $(1,\pm1,)$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.