## Calculus 8th Edition

Foci: $( 1,\pm \sqrt 2)$ and vertices: $(1,\pm1,)$
Given: $x^2-2x=y^2-2$ $\frac{(y-0)^{2}}{1^2}-\frac{(x-1)^{2}}{1^2}=1$, which represents an equation of an hyperbola with $c^{2}=1+1=2$ or, $c=\sqrt 2$ Hence, Foci: $( 1,\pm \sqrt 2)$ and vertices: $(1,\pm1,)$