Answer
$x^2=-12(y-3)$
Work Step by Step
An equation of parabola when the distance of the point $(x,y)$ from the line $y=6$ is $|y-6|$
Thus,$|y-6|=\sqrt {x^2+y^{2}}$
so, $x^2=-12y+36=-12(y-3)$
$|y-6|=\sqrt {x^2+y^{2}}$
Hence, $x^2=-12(y-3)$
Calculus 8th Edition
by Stewart, James
Published by
Cengage
ISBN 10:
1285740629
ISBN 13:
978-1-28574-062-1
Chapter 10 - Parametric Equations and Polar Coordinates - 10.5 Conic Sections - 10.5 Exercises - Page 720: 32
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
