Calculus 8th Edition

Published by Cengage
ISBN 10: 1285740629
ISBN 13: 978-1-28574-062-1

Chapter 10 - Parametric Equations and Polar Coordinates - 10.5 Conic Sections - 10.5 Exercises - Page 720: 32



Work Step by Step

An equation of parabola when the distance of the point $(x,y)$ from the line $y=6$ is $|y-6|$ Thus,$|y-6|=\sqrt {x^2+y^{2}}$ so, $x^2=-12y+36=-12(y-3)$ $|y-6|=\sqrt {x^2+y^{2}}$ Hence, $x^2=-12(y-3)$
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