Calculus 8th Edition

Published by Cengage
ISBN 10: 1285740629
ISBN 13: 978-1-28574-062-1

Chapter 10 - Parametric Equations and Polar Coordinates - 10.5 Conic Sections - 10.5 Exercises - Page 720: 33

Answer

$$y^2=-12(x+1)$$

Work Step by Step

The equation of parabola when the distance of the point $(x,y)$ from the line $x=2$ is $|x-2|$ Thus, $|x-2|=\sqrt {(x+4)^2+y^{2}}$ Hence, $y^2=-12x-12=-12(x+1)$
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