Answer
$\dfrac{x^{2}}{25}+\dfrac{y^{2}}{21}=1$,
which represents an equation of ellipse.
Work Step by Step
From the given vertices : $(\pm\sqrt 5,0)$ we find that $a=5$
This means Foci: $( \pm 2,0)$ with $c=2$
Thus, $b^2=a^2-c^2=25-4=21$
$\dfrac{x^{2}}{25}+\dfrac{y^{2}}{21}=1$,
which represents an equation of ellipse.
