Calculus 8th Edition

Published by Cengage
ISBN 10: 1285740629
ISBN 13: 978-1-28574-062-1

Chapter 10 - Parametric Equations and Polar Coordinates - 10.5 Conic Sections - 10.5 Exercises - Page 720: 13

Answer

Foci: $( \pm \sqrt 8,0)=( \pm 2 \sqrt 2,0)$ Vertices : $( \pm 3,0)$
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Work Step by Step

$x^2+9y^2=0$ Rewrite as $\frac{x^2}{9}+\frac{y^2}{1}=1$ $\frac{x^2}{(3)^2}+\frac{y^2}{(1)^2}=1$ $c^2=a^2-b^2=9-1=8$ $c=\sqrt 8$ Foci: $( \pm \sqrt 8,0)=( \pm 2 \sqrt 2,0)$ Vertices : $( \pm 3,0)$
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