## Calculus 8th Edition

$y ^2 = 4x$
As we are given that the parabola is laterally oriented and the focus is to the right of the vertex. Since, the focus is $(1,0)$ and the vertex is $(0,0)$. Therefore, $h=k=0$ and $p=1$. The equation of a parabola becomes after plug in the values: $(y -0)^2 = 4(1)(x -0)$ Hence, $y ^2 = 4x$