Answer
$y=\frac{x}{27 \ln 3} - \frac{1}{\ln 3} +3$
Work Step by Step
$y=\frac{\ln x}{ln 3}$
$y’=\frac{1}{x \ln 3}$
$y’(27)=\frac{1}{27 \ln 3}$
Equation of tangent:
$y-3=\frac{1}{27 \ln 3} (x-27)$
$y=\frac{x}{27 \ln 3} - \frac{1}{\ln 3} +3$
Calculus 10th Edition
by Larson, Ron; Edwards, Bruce H.
Published by
Brooks Cole
ISBN 10:
1-28505-709-0
ISBN 13:
978-1-28505-709-5
Chapter 5 - Logarithmic, Exponential, and Other Transcendental Functions - 5.5 Exercises - Page 362: 61
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