Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 5 - Logarithmic, Exponential, and Other Transcendental Functions - 5.5 Exercises: 61

Answer

$y=\frac{x}{27 \ln 3} - \frac{1}{\ln 3} +3$

Work Step by Step

$y=\frac{\ln x}{ln 3}$ $y’=\frac{1}{x \ln 3}$ $y’(27)=\frac{1}{27 \ln 3}$ Equation of tangent: $y-3=\frac{1}{27 \ln 3} (x-27)$ $y=\frac{x}{27 \ln 3} - \frac{1}{\ln 3} +3$
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