Answer
$y’= -4 ln 5 (5^{-4x})$
Work Step by Step
$y=5^{-4x}$
$ln y = -4x \ln 5$
$\frac{dy}{y}=-4 \ln 5$
$dy = -4y \ln 5 $
$y’= -4 ln 5 (5^{-4x})$
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