Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 5 - Logarithmic, Exponential, and Other Transcendental Functions - 5.5 Exercises: 30

Answer

$6.932$

Work Step by Step

$(1+\frac{0.10}{365})^{365t}=2$ $\log_{\frac{365.1}{365}}2=365t$ $t=\frac{\log_{\frac{365.1}{365}}2}{365}$ $\approx 6.93242128$ $=6.932$
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