Answer
$6.932$
Work Step by Step
$(1+\frac{0.10}{365})^{365t}=2$
$\log_{\frac{365.1}{365}}2=365t$
$t=\frac{\log_{\frac{365.1}{365}}2}{365}$
$\approx 6.93242128$
$=6.932$
Calculus 10th Edition
by Larson, Ron; Edwards, Bruce H.
Published by
Brooks Cole
ISBN 10:
1-28505-709-0
ISBN 13:
978-1-28505-709-5
Chapter 5 - Logarithmic, Exponential, and Other Transcendental Functions - 5.5 Exercises - Page 362: 30
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