Answer
$=\frac{1}{\ln 2}\left(\frac{x-2}{x(x-1)}\right)$
Work Step by Step
$f(x)=\frac{\ln(\frac{x^2}{x-1})}{\ln 2}$
$=\frac{1}{\ln 2}(2\ln x - ln (x-1))$
$fâ(x)=\frac{1}{\ln 2} (\frac{2}{x}-\frac{1}{x-1})$
$=\frac{1}{\ln 2}\left(\frac{2x-2-x}{x(x-1)}\right)$
$=\frac{1}{\ln 2}\left(\frac{x-2}{x(x-1)}\right)$