Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 5 - Logarithmic, Exponential, and Other Transcendental Functions - 5.5 Exercises - Page 362: 31

Answer

$33$

Work Step by Step

$log_{2}(x-1)=5$ $2^5=x-1$ $x=1+2^5$ $=33$
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