Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 5 - Logarithmic, Exponential, and Other Transcendental Functions - 5.5 Exercises: 42

Answer

$y'=(6^{-2x})(1-2x \ln 6)$

Work Step by Step

$y=x(6^{-2x})$ $u=x$ $u’=1$ $v=6^{-2x}$ $v’=-2\ln 6 (6^{-2x})$ $y’=u’v+uv’$ $=(1)(6^{-2x})+(x)(-2)(\ln 6)(6^{-2x})$ $=(6^{-2x})(1-2x \ln 6)$
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