Answer
$y'=(6^{-2x})(1-2x \ln 6)$
Work Step by Step
$y=x(6^{-2x})$
$u=x$
$u’=1$
$v=6^{-2x}$
$v’=-2\ln 6 (6^{-2x})$
$y’=u’v+uv’$
$=(1)(6^{-2x})+(x)(-2)(\ln 6)(6^{-2x})$
$=(6^{-2x})(1-2x \ln 6)$
Calculus 10th Edition
by Larson, Ron; Edwards, Bruce H.
Published by
Brooks Cole
ISBN 10:
1-28505-709-0
ISBN 13:
978-1-28505-709-5
Chapter 5 - Logarithmic, Exponential, and Other Transcendental Functions - 5.5 Exercises - Page 362: 42
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