Answer
$f'(x)=(9^{x}(1+x \ln 9)$
Work Step by Step
$f(x)=x9^{x}$
$u=x$
$u’=1$
$v=9^x $
$v’=\ln 9 (9^{x}$
$f’(x)=u’v+uv’$
$=(1)(9^{x})+(x)(9^{x}(\ln 9)$
$=(9^{x}(1+x \ln 9)$
Calculus 10th Edition
by Larson, Ron; Edwards, Bruce H.
Published by
Brooks Cole
ISBN 10:
1-28505-709-0
ISBN 13:
978-1-28505-709-5
Chapter 5 - Logarithmic, Exponential, and Other Transcendental Functions - 5.5 Exercises - Page 362: 41
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