Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 5 - Logarithmic, Exponential, and Other Transcendental Functions - 5.5 Exercises - Page 362: 41


$f'(x)=(9^{x}(1+x \ln 9)$

Work Step by Step

$f(x)=x9^{x}$ $u=x$ $u’=1$ $v=9^x $ $v’=\ln 9 (9^{x}$ $f’(x)=u’v+uv’$ $=(1)(9^{x})+(x)(9^{x}(\ln 9)$ $=(9^{x}(1+x \ln 9)$
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