Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 5 - Logarithmic, Exponential, and Other Transcendental Functions - 5.5 Exercises - Page 362: 29

Answer

$12.253$

Work Step by Step

$(a+\frac{0.09}{12})^{12t}=3$ $\log_{1+\frac{0.09}{12}}3=12t$ $t=\frac{\log_{1+\frac{0.09}{12}}3}{12}$ $\approx 12.25252171$ $=12.253$
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