Answer
$y=(-2 \ln 2)x-2 (\ln2 -1)$
Work Step by Step
$y=2^{-x}$
$y’=-\ln 2 (2^{-x})$
$y’(2) = \ln 2 (2^{-(-1)})$
$=-2 \ln 2$
$=14$
Equation of tangent:
$y-2=-2 \ln 2(x+1)$
$y=(-2 \ln 2)x-2 (\ln2 -1)$
Calculus 10th Edition
by Larson, Ron; Edwards, Bruce H.
Published by
Brooks Cole
ISBN 10:
1-28505-709-0
ISBN 13:
978-1-28505-709-5
Chapter 5 - Logarithmic, Exponential, and Other Transcendental Functions - 5.5 Exercises - Page 362: 59
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