Chapter 5 - Logarithmic, Exponential, and Other Transcendental Functions - 5.5 Exercises - Page 362: 23

a. $x=-1$, $x=2$ b. $x=\frac{1}{3}$

a. $x^2-x=\log_{5}25$ $5^{x^2-x}=25$ $5^{x^2-x}=5^2$ $x^2-x=2$ $x^2-x-2=0$ $(x+1)(x-2)=0$ x=-1, x=2 --------------- b. $3x+5=\log_{2}64$ $2^{3x+5}=64$ $2^{3x+5}=2^6$ $3x+5=6$ $3x=1$ $x=\frac{1}{3}$