Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 5 - Logarithmic, Exponential, and Other Transcendental Functions - 5.5 Exercises: 50

Answer

$g’(t)=\frac{6t}{(t^2+7)(\ln 2)}$

Work Step by Step

$g(t)=\frac{3\ln(t^2+7)}{\ln 2}$ $u=3\ln(t^2+7)$ $u’=\frac{6t}{t^2+7}$ $v=\ln 2$ $v’=0$ $g’(t)=\frac{u’v-uv’}{v^2}$ $=\frac{\left(\frac{6t}{t^2+7}\right)(\ln 2)-(3)(\ln(t^2+7))(0)}{(\ln 2)^2}$ $g’(t)=\frac{6t}{(t^2+7)(\ln 2)}$
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