Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 5 - Logarithmic, Exponential, and Other Transcendental Functions - 5.5 Exercises - Page 362: 50


$g’(t)=\frac{6t}{(t^2+7)(\ln 2)}$

Work Step by Step

$g(t)=\frac{3\ln(t^2+7)}{\ln 2}$ $u=3\ln(t^2+7)$ $u’=\frac{6t}{t^2+7}$ $v=\ln 2$ $v’=0$ $g’(t)=\frac{u’v-uv’}{v^2}$ $=\frac{\left(\frac{6t}{t^2+7}\right)(\ln 2)-(3)(\ln(t^2+7))(0)}{(\ln 2)^2}$ $g’(t)=\frac{6t}{(t^2+7)(\ln 2)}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.