Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 5 - Logarithmic, Exponential, and Other Transcendental Functions - 5.5 Exercises - Page 362: 1

Answer

-3

Work Step by Step

$\log_2{\frac{1}{8}} = \log_2{2^{-3}} = -3$
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