Answer
$y’=\frac{5}{(ln 4)(5x+1)}$
Work Step by Step
$y=\frac{\ln(5x+1)}{\ln 4}$
$u=\ln(5x+1)$
$u’=\frac{5}{5x+1}$
$v=\ln 4$
$v’=0$
$y’=\frac{u’v-uv’}{v}$
$=\frac{(\frac{5}{5x+1})(ln 4)-(\ln(5x+1))(0)}{(\ln 4)^2}$
$y’=\frac{5}{(ln 4)(5x+1)}$
Calculus 10th Edition
by Larson, Ron; Edwards, Bruce H.
Published by
Brooks Cole
ISBN 10:
1-28505-709-0
ISBN 13:
978-1-28505-709-5
Chapter 5 - Logarithmic, Exponential, and Other Transcendental Functions - 5.5 Exercises - Page 362: 47
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