Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 13 - Functions of Several Variables - 13.5 Exercises - Page 913: 1

Answer

$$\frac{dw}{dt}=26t$$ When $t=2$ $$\frac{dw}{dt}=52$$

Work Step by Step

Using the chain rule we have $$\frac{dw}{dt}=\frac{\partial w}{\partial x}\frac{dx}{dt}+\frac{\partial w}{\partial y}\frac{dy}{dt}=\frac{\partial }{\partial x}(x^2+y^2)\frac{d}{dt}(2t)+\frac{\partial }{\partial y}(x^2+y^2)\frac{d}{dt}(3t)=2x\cdot2+2y\cdot3=4x+6y$$ Expressing this in terms of $t$ we have: $$\frac{dw}{dt}=4\cdot2t+6\cdot3t=8t+18t=26t$$ When $t=2$ we have: $$\frac{dw}{dt}=26\cdot2=52$$
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