Answer
$x^{2}$ + y - 4 = 0
Work Step by Step
The vertex is at (0,4) and has two points: (-2,0) and (2,0). Therefore, the parabola has a vertical axis.
$(x-0)^{2}$ = 4p(y-4)
$2^{2}$ = 4p $\times$ (0-4)
4 = -16p
p = -$\frac{1}{4}$
$x^{2}$ = -(y-4)
$x^{2}$ + y - 4 = 0
