Answer
$y^2-8y+8x-24=0$
Work Step by Step
$(y-4)^2=4(-2)(x-5)$
$y^2-8y+16=-8x+40$
$y^2-8y+8x-24=0$
Calculus 10th Edition
by Larson, Ron; Edwards, Bruce H.
Published by
Brooks Cole
ISBN 10:
1-28505-709-0
ISBN 13:
978-1-28505-709-5
Chapter 10 - Conics, Parametric Equations, and Polar Coordinates - 10.1 Exercises - Page 692: 15
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