Answer
$x^2-32y+160=0$
Work Step by Step
$(x-0)^2=4(8)(y-5)$
$x^2=4(8)(y-5)$
$x^2-32y+160=0$
Calculus 10th Edition
by Larson, Ron; Edwards, Bruce H.
Published by
Brooks Cole
ISBN 10:
1-28505-709-0
ISBN 13:
978-1-28505-709-5
Chapter 10 - Conics, Parametric Equations, and Polar Coordinates - 10.1 Exercises - Page 692: 17
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