Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 7 - Section 7.3 - Multiplying and Simplifying Radical Expressions - Exercise Set - Page 531: 87

Answer

$-6x^3y^3\sqrt {2}$.

Work Step by Step

The given expression is $=(-2xy^2\sqrt {3x})(xy\sqrt {6x})$ Clear the parentheses. $=-2x^2y^3\sqrt {3x}\sqrt {6x}$ Apply the product rule of radicals. $\sqrt a \cdot \sqrt b = \sqrt {ab}$ $=-2x^2y^3\sqrt {3x\cdot 6x}$ Find the square factors. $=-2x^2y^3\sqrt {3^2x^22}$ Factor into two radicals. $=-2x^2y^3\sqrt {3^2x^2}\sqrt {2}$ Simplify. $=-2x^2y^3\cdot 3x\sqrt {2}$ $=-6x^3y^3\sqrt {2}$.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.