## Intermediate Algebra for College Students (7th Edition)

$\sqrt[7]{77x^5y^3}$
RECALL: (i) For nonegative numbers a and b, $\sqrt[n]{a} \cdot \sqrt[n]{b} = \sqrt[n]{ab}$ (ii) $a^m \cdot a^n = a^{m+n}$ Use the rules above to obtain: $=\sqrt[7]{(7x^2y)(11x^3y^2)} \\=\sqrt[7]{77x^{2+3}y^{1+2}} \\=\sqrt[7]{77x^5y^3}$