Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 7 - Section 7.3 - Multiplying and Simplifying Radical Expressions - Exercise Set: 48

Answer

$xy^5\sqrt[3]{y^2z^2}$

Work Step by Step

Factor the radicand (expression inside the radical sign) so that at least one factor is a perfect cube, and then simplify to obtain: $=\sqrt[3]{x^{3}y^{15}(y^2z^2)} \\=\sqrt[3]{(xy^5)^3(y^2z^2)} \\=xy^5\sqrt[3]{y^2z^2}$
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