Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 7 - Section 7.3 - Multiplying and Simplifying Radical Expressions - Exercise Set: 50

Answer

$2x^3y^5\sqrt[3]{4y^2}$

Work Step by Step

Write 32 as $2^5$ to obtain: $=\sqrt[3]{2^5x^9y^{17}}$ Factor the radicand (expression inside the radical sign) so that at least one factor is a perfect cube, and then simplify to obtain: $=\sqrt[3]{(2^3x^9y^{15})\cdot 2^2y^2} \\=\sqrt[3]{2^3(x^3)^3(y^5)^3 \cdot 4y^2} \\=2x^3y^5\sqrt[3]{4y^2}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.