Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 7 - Section 7.3 - Multiplying and Simplifying Radical Expressions - Exercise Set - Page 531: 69



Work Step by Step

RECALL: For any non-negative real numbers a and b, $\sqrt[n]{a} \cdot \sqrt[n]{b} = \sqrt[n]{ab}$ Use the rule above to obtain: $=2\cdot 3\sqrt{(5)(40)} \\=6\sqrt{200}$ Factor the radicand (expression inside the radical sign) so that at least one factor is a perfect square, and then simplify to obtain: $=6\sqrt{100(2)} \\=6\cdot 10\sqrt{2} \\=60\sqrt{2}$
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