Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 7 - Section 7.3 - Multiplying and Simplifying Radical Expressions - Exercise Set - Page 531: 18

Answer

$\sqrt[4]{\dfrac{7x}{3y}}$

Work Step by Step

RECALL: For nonegative numbers a and b, $\sqrt[n]{a} \cdot \sqrt[n]{b} = \sqrt[n]{ab}$ Use the rule above to obtain: $=\sqrt[4]{\dfrac{x}{3} \cdot \dfrac{7}{y}} \\=\sqrt[4]{\dfrac{7x}{3y}}$
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