## Intermediate Algebra for College Students (7th Edition)

$|x^3|\sqrt{x}$
Factor the radicand (expression inside the radical sign) so that at least one factor is a square to obtain: $=\sqrt{x^6(x)} \\=\sqrt{(x^3)^2(x)}$ The principal square root is always non-negative. Thus, apply the absolute value to the square root of $(x^3)^2$ to obtain: $=|x^3|\sqrt{x}$