## Intermediate Algebra for College Students (7th Edition)

$4|x|\sqrt{3x}$
Factor the radicand (expression inside the radical sign) so that at least one factor is a square to obtain: $=\sqrt{16x^2(3x)} \\=\sqrt{4^2x^2(3x)}$ The principal square root is always non-negative. Thus, to make sure that the principal square root of $x^2$ is non-negative, use absolute value bars to obtain: $=4|x|\sqrt{3x}$