#### Answer

$2x^2\sqrt[4]{6x^3}$

#### Work Step by Step

Write $96$ as $16(6)$ to obtain:
$=\sqrt[4]{16(6)x^{11}}
\\=\sqrt[4]{2^4(6)x^{11}}$
RECALL:
$\sqrt[n]{a^n}=a$
Factor the radicand (expression inside the radical sign) so that at least one factor is a perfect fourth power, and then use the rule above to simplify and obtain:
$=\sqrt[4]{(2^4x^8) \cdot 6x^3}
\\=\sqrt[4]{2^4(x^2)^4 \cdot 6x^3}
\\=2x^2\sqrt[4]{6x^3}$