Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 7 - Section 7.3 - Multiplying and Simplifying Radical Expressions - Exercise Set: 20

Answer

$\sqrt[9]{36x^5y^7}$

Work Step by Step

RECALL: (i) For nonegative numbers a and b, $\sqrt[n]{a} \cdot \sqrt[n]{b} = \sqrt[n]{ab}$ (ii) $a^m \cdot a^n = a^{m+n}$ Use the rules above to obtain: $=\sqrt[9]{(12x^2y^3)(3x^3y^4)} \\=\sqrt[9]{36x^{2+3}y^{3+4}} \\=\sqrt[9]{36x^5y^7}$
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