Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 7 - Section 7.3 - Multiplying and Simplifying Radical Expressions - Exercise Set: 70

Answer

$45\sqrt{10}$

Work Step by Step

RECALL: For any non-negative real numbers a and b, $\sqrt[n]{a} \cdot \sqrt[n]{b} = \sqrt[n]{ab}$ Use the rule above to obtain: $=3\cdot 5\sqrt{(15)(6)} \\=15\sqrt{90}$ Factor the radicand (expression inside the radical sign) so that at least one factor is a perfect square, and then simplify to obtain: $=15\sqrt{9(10)} \\=15 \cdot 3\sqrt{10} \\=45\sqrt{10}$
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