Answer
$(2x-4)\sqrt[3]{6}$
Work Step by Step
Factor the expression inside the radical so that at least one factor is a perfect cube, and then simplify to obtain:
$=\sqrt[3]{8(x-2)^3(6)}
\\=\sqrt[3]{2^3(x-2)^3(6)}
\\=2(x-2)\sqrt[3]{6}
\\=(2x-4)\sqrt[3]{6}$
