## Intermediate Algebra for College Students (7th Edition)

$2\sqrt[3]{6}$
RECALL: For any non-negative real numbers a and b, $\sqrt[n]{a} \cdot \sqrt[n]{b} = \sqrt[n]{ab}$ Use the rule above to obtain: $=\sqrt[3]{(12)(4)} \\=\sqrt[3]{48}$ Factor the radicand (expression inside the radical sign) so that at least one factor is a cube, and then simplify to obtain: $\\=\sqrt[3]{8(6)} \\=\sqrt[3]{2^3(6)} \\=2\sqrt[3]{6}$