Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 7 - Section 7.3 - Multiplying and Simplifying Radical Expressions - Exercise Set - Page 531: 71

Answer

$2\sqrt[3]{6}$

Work Step by Step

RECALL: For any non-negative real numbers a and b, $\sqrt[n]{a} \cdot \sqrt[n]{b} = \sqrt[n]{ab}$ Use the rule above to obtain: $=\sqrt[3]{(12)(4)} \\=\sqrt[3]{48}$ Factor the radicand (expression inside the radical sign) so that at least one factor is a cube, and then simplify to obtain: $\\=\sqrt[3]{8(6)} \\=\sqrt[3]{2^3(6)} \\=2\sqrt[3]{6}$
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