Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 7 - Review Exercises - Page 576: 7


$g(4)=2$ $g(0)=-2$ $g(-14)=-4$

Work Step by Step

Given: $\sqrt[3]{4x-8}$ Need to find $g(4), g(0),g(-14)$. $g(4)=\sqrt[3]{4(4)-8}=2$ $g(0)=\sqrt[3]{4(0)-8}=-2$ $g(-14)=\sqrt[3]{4(-14)-8}=-4$
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