## Intermediate Algebra for College Students (7th Edition)

$g(4)=2$ $g(0)=-2$ $g(-14)=-4$
Given: $\sqrt[3]{4x-8}$ Need to find $g(4), g(0),g(-14)$. $g(4)=\sqrt[3]{4(4)-8}=2$ $g(0)=\sqrt[3]{4(0)-8}=-2$ $g(-14)=\sqrt[3]{4(-14)-8}=-4$