Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 7 - Review Exercises - Page 576: 5

Answer

$-2$

Work Step by Step

Since, $(-1 \cdot 2)^5=-(2)^5=-32$ Thus, $\sqrt[5] {(-32)}=-2$
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