Answer
$|x-4|$
Work Step by Step
As per definition of square root property,we have $\sqrt {x^2}=|x|$
Given: $x^2-8x+16$
Which can be written as: $x^2-8x+16=x^2-2(x)(4)+4^2$
or, $(x-4)^2$
Thus, $\sqrt{(x^2-8x+16)^2}=\sqrt{(x-4)^2}=|x-4|$
Intermediate Algebra for College Students (7th Edition)
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-13417-894-7
ISBN 13:
978-0-13417-894-3
Chapter 7 - Review Exercises - Page 576: 12
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