## Intermediate Algebra for College Students (7th Edition)

$f(15)=5$ $f(4)=\sqrt 3$ $f(\dfrac{5}{2})=0$ $f(1)=\sqrt{-3}$; not a real number
Given: $\sqrt{2x-5}$ Need to find $f(15),f(4), f(\dfrac{5}{2}),f(1)$. $f(15)=\sqrt{2(15)-5}=5$ $f(4)=\sqrt{2(4)-5}=\sqrt 3$ $f(\dfrac{5}{2})=\sqrt{2(\dfrac{5}{2})-5}=0$ $f(1)=\sqrt{2(1)-5}=\sqrt{-3}$; not a real number