Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 7 - Review Exercises - Page 576: 19

Answer

$(7x)^{\frac{1}{2}}$

Work Step by Step

As per definition of square root property,we have $\sqrt {p}=(p)^{\frac{1}{2}}$ Thus, the given radical term can be written as: Hence, $\sqrt {7x}=(7x)^{\frac{1}{2}}$
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