Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 7 - Review Exercises - Page 576: 17

Answer

$64$

Work Step by Step

As per definition of square root property,we have ${p}^{\frac{3}{2}}=\sqrt {p^3}$ Thus, the given radical term can be written as: $(16)^{\frac{3}{2}}=\sqrt {16^3}=4^3$ or, $=64$ Thus, $\sqrt {16^3}=64$
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