Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 7 - Review Exercises - Page 576: 23

Answer

$x^{\frac{7}{12}}$

Work Step by Step

Simplify. $(x)^{\frac{1}{3}} \cdot(x)^{\frac{1}{4}} $ Since, the power raised to a same exponent gets add. $(m)^\frac{p}{q}(m)^\frac{r}{s}=(m)^{\frac{p}{q}+\frac{r}{s}}$ Thus, $(x)^{\frac{1}{3}} \cdot(x)^{\frac{1}{4}} =(x)^{\frac{1}{3}+\frac{1}{4}}=x^{\frac{4+3}{12}}$ Hence, $=x^{\frac{7}{12}}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.