Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 7 - Review Exercises - Page 576: 32

Answer

$3150$ million dollars

Work Step by Step

Need to find $f(27)$. We have $x=2012-1985=27$ years Thus, $f(27)=350(27)^\frac{2}{3}$ Since, the power raised to a each base gets multiply such as $(ab)^n=a^nb^n$ Thus, or, $=350(3^3)^\frac{2}{3}$ or, $=350(3)^\frac{6}{3}$ This implies that or, $f(27)=3150$ million dollars
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