Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 7 - Review Exercises - Page 576: 29

Answer

$\sqrt[6]{x^5}$

Work Step by Step

Simplify. $\sqrt x \sqrt[3]{x}$ As per definition of square root property,we have $(p)^{\frac{m}{n}}=(\sqrt[n] {p})^m$ Thus, the given radical term can be written as: $\sqrt x \sqrt[3]{x}={x^\frac{1}{2}}(x)^\frac{2}{3}$ Since, the power raised to a same exponent gets add. or,$=x^{\frac{1}{2}+\frac{2}{3}}$ or, $=x^\frac{3+2}{6}$ or, $=x^\frac{5}{6}$ Hence, the above exponent in radical notation can be written as: $\sqrt[6]{x^5}$
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