Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 7 - Review Exercises - Page 576: 33

Answer

$\sqrt{21xy}$

Work Step by Step

Simplify. $\sqrt {3x}\sqrt{7y}$ Thus, As per the product rule, we have $\sqrt[n] {pq}=\sqrt[n] {p}\sqrt[n] {q}$ $\sqrt {3x}\sqrt{7y}=\sqrt{(3x)(7y)}=\sqrt{21xy}$
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