Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 7 - Review Exercises - Page 576: 18

Answer

$16$

Work Step by Step

As per definition of square root property,we have $(p)^{\frac{m}{n}}=(\sqrt[n] {p})^m$ Thus, the given radical term can be written as: $(32)^{\frac{4}{5}}=(\sqrt[5] {32})^4=(\sqrt[5] {2^5})^4=2^4$ This implies, $=16$ Hence, $(32)^{\frac{4}{5}}=16$
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