Answer
$x^3y^4$
Work Step by Step
Simplify. $\sqrt[3]{x^9y^{12}}$
Since, the power raised to a same exponent or base gets subtract when they are divide and the power raised to a each base gets add.
As per definition of square root property,we have $(p)^{\frac{m}{n}}=(\sqrt[n] {p})^m$
Thus, the given radical term can be written as:
$\sqrt[3]{x^9y^{12}}=\sqrt[3]{x^9}\sqrt[3]{y^{12}}$
or,$=x^{\frac{9}{3}}y^{\frac{12}{3}}$
Hence, $=x^3y^4$
