Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 7 - Review Exercises - Page 576: 13

Answer

$4x$

Work Step by Step

As per the product rule, we have $\sqrt[n] {pq}=\sqrt[n] {p}\sqrt[n] {q}$ Given: $\sqrt[3] {64x^3}$ Which can be written as: $\sqrt[3] {64x^3}=\sqrt[3] {64}\sqrt[3] {x^3}$ or, $=\sqrt[3] {4^3}\sqrt[3] {x^3}$ or, $=4x$
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