Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 7 - Review Exercises - Page 576: 25



Work Step by Step

Simplify. $(8x^6y^3)^{\frac{1}{3}} $ Since, the power raised to a each base gets multiply such as $(ab)^n=a^nb^n$ Thus, $(8x^6y^3)^{\frac{1}{3}}=(2^3)^{\frac{1}{3}}(x^6)^{\frac{1}{3}}(y^3)^{\frac{1}{3}}$ or,$=(2)(x)^\frac{6}{3}(y)^\frac{3}{3}$ Hence, $=2x^2y$
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