## Intermediate Algebra for College Students (7th Edition)

$2x^2y$
Simplify. $(8x^6y^3)^{\frac{1}{3}}$ Since, the power raised to a each base gets multiply such as $(ab)^n=a^nb^n$ Thus, $(8x^6y^3)^{\frac{1}{3}}=(2^3)^{\frac{1}{3}}(x^6)^{\frac{1}{3}}(y^3)^{\frac{1}{3}}$ or,$=(2)(x)^\frac{6}{3}(y)^\frac{3}{3}$ Hence, $=2x^2y$